Question

# A condenser of  $$250 \mu F$$ is connected in parallel to a coil of inductance  0.16 mH, while its effective resistance is $$20 \Omega$$. Determine the resonant frequency.

A
9×104Hz
B
16×107Hz
C
8×105Hz
D
9×103Hz

Solution

## The correct option is B $$8\times 10^5 Hz$$For the given case we have standard formula for resonant frequency as:$$f\:=\dfrac{1}{2\pi}\:\sqrt{\dfrac{1}{LC}-\dfrac{R^2}{L^2}}$$ $$f\:=\dfrac{1}{2\pi}\:\sqrt{\dfrac{1}{0.16\times 10^{-3}\times 250\times 10^{-6}}-\dfrac{400}{({0.16\times10^{-3}})^{2}}}$$ On directly putting the given values in he equation we get:$$\omega\:=\:7.98\times10^5$$Physics

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