Question

A conducting rod PQ of length L = 1.0 m is moving with uniform speed v = 2.0 $m{s}^{-1}$ in a uniform magnetic field B = 4.0 T directed into the paper. A capacitor of capacity C = 10 $\mu$F is connected as shown in the figure. Then after a long time charge on plates of capacitor is

• A. q_A = + 80 μ C and q_B = - 80 μC
• B. q_A = - 80 μ C and q_B = +80 μC
• C. q_A = q_B = 0
• D. Charge stored in the capacitor can’t be determined

Answer 1

The correct option is A

q_A = + 80 μ C and q_B = - 80 μC

EMF=Bvl

And q=cV