A constant current exists in a inductor-coil connected to a battery. The coil is short-circuited and the battery is removed. Show that the charge flown through the coil after the short-circuiting is the same as that which flows in one time constant before the short-circuiting.
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In this case there is no resistor in the circuit So, the energy stored due to the inductor before and after removal of battery remains same V1=V2=12Li2 So, the current will also remain same Thus charge flowing through the conductor is the same