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Question

# A constant force 10 N acts on a ball of mass 2 kg for 2 s . Then another force 18 N acts on the same ball for 109 second. If ball is initially at rest, then find the total work done.

A
400 J
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B
300 J
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C
200 J
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D
100 J
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Solution

## The correct option is A 400 JWhen F1=10 N acts on the ball a1=F1/m=5 m/s2 v1=uo+at =0+5×2 (∵uo=0) v1=10 m/s Now, v21−u2o=2aS1 ⇒102−02=2×5×S1 ⇒S1=10 m Work done by F1=F1×S1=10×10 W1=100 J Again, when F2=18 N acts on ball, a2=F2/m=182=9 m/s2 S2=v1t+12at2=10(109)+12(9)(109)2=1509=503 Work done by force W2=F2×S2 W2=503×18=300 J Total work done = W1+W2=300+100=400 J

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