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Question

A constant power P is applied to a particle of mass m. The distance travelled by the particle when its velocity increases from v1 to v2 is (neglect friction)

A
m3P(v32v31)
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B
m3P(v2v1)
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C
3Pm(v22v21)
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D
m3P(v22v21)
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Solution

The correct option is A m3P(v32v31)
Constant power P=Fv=mav
So, we get a=Pmv
or vdvds=Pmv
or v2dv=Pmds
Integrating on both sides, we get
Pms0ds=v2v1v2dv
or
or Pms=13(v32v31)
Thus we get s=m3P(v32v31)

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