Question

# A constant torque acting on a uniform circular wheel changes its angular momentum from $$A_0$$ to $$4A_0$$ in $$4$$ sec. The magnitude of this torque is:

A
4A0
B
A0
C
34A0
D
12A0

Solution

## The correct option is C $$\dfrac{3}{4}A_0$$Change in angular momentum   $$\Delta L = L_f-L_i = 4A_o-A_o = 3A_o$$Time taken  $$\Delta T = 4 \ s$$Magnitude of torque  $$\tau = \dfrac{\Delta L}{\Delta T} = \dfrac{3A_o}{4}$$Physics

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