CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

A constant torque acting on a uniform circular wheel changes its angular momentum from $$A_0$$ to $$4A_0$$ in $$4$$ sec. The magnitude of this torque is:


A
4A0
loader
B
A0
loader
C
34A0
loader
D
12A0
loader

Solution

The correct option is C $$\dfrac{3}{4}A_0 $$
Change in angular momentum   $$\Delta L = L_f-L_i = 4A_o-A_o = 3A_o$$
Time taken  $$\Delta T = 4 \ s$$
Magnitude of torque  $$\tau = \dfrac{\Delta L}{\Delta T} = \dfrac{3A_o}{4}$$

Physics

Suggest Corrections
thumbs-up
 
0


similar_icon
Similar questions
View More


similar_icon
People also searched for
View More



footer-image