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Question

A container contains 0.2 mol of CO2 and 0.1 mol H2 and establish following equilibrium.
CO2(g)+H2(g)CO(g)+H2O(g). At equlibrium H2O is found to be 25% by mol. The equilibrium constant Kp for the reaction is 


Solution

Given,
CO2(g)+H2(g)CO(g)+H2O(g)0.20.1000.2x0.1xxx
According to the question,x0.3×100=25x=0.075 or 3/40
So,Kp=x2(0.2x)(0.1x)=(3/40)21/8×1/40=1.8

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