CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A container contains two immiscible liquids of density ρ1 and ρ2 (ρ2>ρ1). A capillary of radius r is inserted in the liquids so that its bottom reaches upto denser liquid. Denser liquid rises in capillary and attains a height h which is also equal to column length of lighter liquid. Assuming zero contact angle, find surface tension of heavier liquid.

A
rρ2gh2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
r2(ρ2ρ1)gh
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
2πrρ2gh
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
2πr(ρ2ρ1)gh
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B r2(ρ2ρ1)gh
Excess pressure due to miniscus is,
P1=P02Tr
Pressure at the interface is
Pc=P1+ρ2gh
Pc=P02Tr+ρ2gh
Pressure at the interface can also be written as,
Pc=ρ1gh+P0
ρ1gh+P0=P02Tr+ρ2gh
ρ2ghρ1gh=2Tr
(ρ2ρ1)gh=2Tr
T=rgh2(ρ2ρ1)

flag
Suggest Corrections
thumbs-up
0
similar_icon
Similar questions
View More
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Fluid Flow
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon