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Question

A container whose capacity is 6060 litre contains milk and water in the ratio 3:2. How much quantity of the mixture should be replaced with pure milk, so that in the final mixture, ratio of milk to water is 7:3?

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Solution

In 60 litre of mixture,
The quantity of milk =35×60
=36 litre

So, the quantity of water will be =6036
=24 litre

Let x liters of mixture is replaced.

So, remaining milk after replacement =3635x+x
=36+2x5

Now, the ratio of milk in comparison with total amount of mixture shoulbe be 7:10 as per the question,
36+2x560=710
36+2x5=42
2x5=4236
2x5=6
x=15 litre

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