A convex lens made of glass of refractive index 1.5 has both surfaces of the same radius of curvature R. In case (i) the lens is immersed in a medium of refractive index 1.25 and in case (ii) it is immersed in a medium of refractive index 1.75. Then,

in case (i) the lens will behave as a convergent lens of focal length 2.5 R.

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in case (ii) the lens will behave as a divergent lens of focal length 3.0 R.

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In case (ii) the lens will behave as a convergent lens of focal length 3 R.

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in case(ii) the lens will behave as a divergent lens of focal length 3.5 R.

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Solution

The correct options are
A
in case (i) the lens will behave as a convergent lens of focal length 2.5 R.

D
in case(ii) the lens will behave as a divergent lens of focal length 3.5 R.

We know Lens maker's formula,

$\frac{1}{f} = (μ - 1) (\frac{1}{R_{1}} - \frac{1}{R_{2}})$

in case (i) the lens will behave as a convergent lens of focal length 2.5 R.

in case(ii) the lens will behave as a divergent lens of focal length 3.5 R.

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