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Question

A copper ball of density pc and diameter d is immersed in oil of density po .What charge should be present on the ball , so that it could be suspended in the oil, if a homogeneous electric field E is applied vertically upward?

A
Q = πd2(pcp0)g6E
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B
Q = πd3(pcp0)g6E
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C
Q = πd3(pcp0)gE
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D
Q = πd2(pcp0)g2E
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Solution

The correct option is A Q = πd2(pcp0)g6E
Copper ball of intensity =PC diameter d.
density =P0
electric field =E
homogeneous electric field E is applied Pressure
P=hpg=(PcP0)×g×πd26
Now,
Q=PE=πd2g(PcP0)6E

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