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Question

A copper ball of mass 100gm is at a temperature T. It is dropped in a copper calorimeter of mass 100gm, filled with 170gm of water at room temperature. Subsequently, the temperature of the system is found to be 75oC. T is given by :
(Given : room temperature =30oC, specific heat of copper =0.1cal/gmoC)

A
825oC
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B
800oC
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C
885oC
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D
1250oC
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Solution

The correct option is B 885oC

The amount of heat last by copper ball =mballCCuΔTball

=(100gm)(0.1cal/gm˚C)(T75)˚C

The amount of heat gained by calorimeter =mcalorieCCuΔTCalorie

=(100gm)(0.1cal/gm˚C)(7530)˚C

Amount of heat gained by water =mwCCuΔTw

=(170gm)(1cal/gm˚C)(7530)˚C

Hence, from conservation of energy,

100×0.1×(T75)=100×0.1×(7530)+170×1×(7530)

T=885˚C

Hence, correct answer is option C.


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