A copper disc of radius 0.1 m rotates about its centre with 10 revolutions per second in a uniform magnetic field of 0.1 Tesla. The emf induced across the radius of the disc is

\frac{π}{10}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{2 π}{10}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

10 π m V

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

20 π m V

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $10 π m V$
The induced emf between centre and rim of the rotating disc is

$E = \frac{1}{2} B w R^{2} = \frac{1}{2} \times 0.1 \times 2 π \times 10 \times (0.1)^{2} = 10 π \times 10^{- 3}$ volt

Suggest Corrections

Similar questions

Q. A copper disc of radius 0.1 m rotates about its centre with 10 revolutions per second in a uniform magnetic field of 0.1 Tesla. The emf induced across the radius of the disc is

A copper disc of radius 0.1 m rotates about its centre with 10 revolutions per second in a uniform magnetic field of 0.1 Tesla. The emf induced across the radius of the disc is

Q. A copper disc of radius

0.1

m

rotated about its centre with

10

revolutions per second in a uniform magnetic field of

0.1

tesla with it's plane perpendicular to the field. The e.m.f. induced across the radius of disc is:

Q. A copper disc of radius

0.1 m

is rotated about its centre at

20

revolutions per second in a uniform magnetic field of

0.1 T

with its plane perpendicular to the field. The emf induced across the radius of the disc is -

Q. A copper disc or radius 0.1 m rotates about its axis in a uniform magnetic field of 0.1. Tesla at 10 rotations per second. the plane of the disc remains normal to the magnetic field. The induced emf along the radius of the disc will be

Join BYJU'S Learning Program

A copper disc of radius 0.1 m rotates about its centre with 10 revolutions per second in a uniform magnetic field of 0.1 Tesla. The emf induced across the radius of the disc is

The correct option is C 10π mVThe induced emf between centre and rim of the rotating disc is E=12BwR2=12× 0.1× 2π× 10× (0.1)2=10π× 10−3volt

The correct option is C $10 π m V$
The induced emf between centre and rim of the rotating disc is

$E = \frac{1}{2} B w R^{2} = \frac{1}{2} \times 0.1 \times 2 π \times 10 \times (0.1)^{2} = 10 π \times 10^{- 3}$ volt