A cord is used to lower vertically a block of mass M by a distance d with constant downward acceleration $\frac{g}{4}$ . Work done by the cord on the block is

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Solution

The correct option is A

When the block noves vertically downward with acceleration $\frac{g}{4}$ then tension in the cord

$T = M (g - \frac{g}{4}) = \frac{3}{4} M g$

Work done by the cord = $\to F . \to s = F s c o s θ$

$= T d c o s (180^{\circ}) = - (\frac{3 M g}{4}) \times d = - 3 M g \frac{d}{4}$

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