Question

A cricket ball of mass $150g$ is moving with a velocity of $12m/s$ and is hit by a bat so that the ball is turned back with a velocity of $20m/s$. The force of blow acts for $0.01s$ on the ball. The average force exerted by the bat on the ball is (in $N$)

• A. $480$
  
• B. $500$
  
• C. $520$
  
• D. $400$
  

Answer 1

The correct option is A $480$

Average force exerted by bat is rate of change of momentum of the ball.

Change in momentum of ball is $\Delta P=m(v-u)$

$\Delta P=0.15\times (20-(-12\left)\right)=\left(0.15\right)\left(32\right)kgm{s}^{-1}$

So, average force is $F=\frac{\Delta P}{\Delta t}=\frac{150\times 32}{1000\times 0.01}=480N$