Question

A cube of aluminium of sides 0.1 m is subjected to a shearing force of 100 N. The top face of the cube is displaced through 0.02 cm with respect to the bottom face. The shearing strain would be

• A. 0.02
• B. 0.1
• C. 0.005
• D. 0.002

Answer 1

The correct option is D

0.002

Shearing strain $\varphi =\frac{x}{L}=\frac{0.02cm}{10cm}\therefore \varphi =0.002$