Question

A cube of side 0.4 m rest on the floor, as shown. Given that the cube has a mass of 200 kg, the pressure exerted by the cube on the floor is -
(Take g= 10 N $k{g}^{-1}$)

• A. 25 N $m^{-2}$
• B. 250 N $m^{-2}$
• C. 1250 N $m^{-2}$
• D. 12500 N $m^{-2}$

Answer 1

The correct option is D 12500 N $m^{-2}$

Mass of cube is given by 200 kg

$g=10$

Force = mass x gravity

$=200x10$

$F=2000N$

The side length of a cube is $0.4m$

A surface area of one face of a cube can be taken as side x side

Area of one face of a cube can be taken as

$0.4\times 0.4=0.16m^2$

Pressure = force / area

$=2000/0.16$

$=12,500N/m^2$

Now the pressure exerted by the cube on the floor is $12,500N/m^2$