CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A cubical block rests on a plane of μ=3. The angle through which the plane be inclined to the horizontal so that the block just slides down will be

A
30
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
45
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
60
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
75
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 60
I Method

The block will have force mgsinθ along the incline plane and the frictional force will have fs=μN
where N=mgcosθ
fs=mgsinθ

For equilibrium

μ mgcosθ=mgsinθ
tanθ=μ=3
θ=60

II Method
This is the case of angle of repose. Angle of repose is defined as the minimum angle of the inclined plane and we have the formulae as tanθ=μ by putting the value of μ=3 we get θ=60

flag
Suggest Corrections
thumbs-up
15
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Friction: A Quantitative Picture
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon