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Question

A cubical vessel of height 1m is full of water. What is the work done in pumping water out of the vessel?


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Solution

Step 1: Given:

Height of the vessel, h=1m

The centre of mass of the water in the cubical vessel lies at CM, i.e h'=h2=12m

The volume water, V=h3=13=1m3

Mass of water,m=ρV=1000×1=1000kg

Step 2: Formula & Solution

Work done for pumping out water is equal to negative of change in its potential energy.

W=ΔP.E=(P.EfP.Ei)=(0mgh')=mgh'=1000×10×12=5000J

Hence,the work done in pumping water out of the vessel is 5000J.


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