A cuboidal fish tank has a length of $30 c m$ , a breadth of $20 c m$ and a height of $20 c m$ . The tank is placed on a horizontal table and it is three-quarters full of water. Find the area of the tank which is in contact with water.

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Solution

Given
Length of tank $= 30 c m$
Breadth of tank $= 20 c m$
Height of tank $= 20 c m$

As the tank is three-quarters full of water
So, the height of water in the tank $= 20 \times \frac{3}{4} = 15 c m$

Hence,
Area of the tank in contact with the water = Area of floor of tank + Area of 4 walls upto $15 c m$
$= 30 \times 20 + 2 (30 + 20) \times 15 = 600 + 2 \times 50 \times 15 = 2100 {c m}^{2}$

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A cuboidal fish tank has a length of 30cm, a breadth of 20cm and a height of 20cm. The tank is placed on a horizontal table and it is three-quarters full of water. Find the area of the tank which is in contact with water.

GivenLength of tank =30cmBreadth of tank =20cmHeight of tank =20cmAs the tank is three-quarters full of waterSo, the height of water in the tank =20×34=15cmHence,Area of the tank in contact with the water = Area of floor of tank + Area of 4 walls upto 15cm=30×20+2(30+20)×15=600+2×50×15=2100cm2

A cuboidal fish tank has a length of $30 c m$ , a breadth of $20 c m$ and a height of $20 c m$ . The tank is placed on a horizontal table and it is three-quarters full of water. Find the area of the tank which is in contact with water.