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Hydrogen Peroxide

A current 9...

Question

A current $9.65$ ampere is passed through the aqueous solution $N a C l$ using suitable electrodes for $1000 s$ . The amount of $N a O H$ formed during electrolysis is:

A

2.0 g

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B

4.0 g

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C

6.0 g

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D

8.0 g

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Solution

The correct option is B $4.0 g$

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Similar questions

Q. A current of 9.65 A is passed through an aqueous solution of

N a C l

using suitable electrodes for 1000 sec. Given that 1 faraday equals 96500 coulombs the amount of

N a O H

(mol wt. 40) formed on electrolysis is:

For how much time,

10

ampere electric current should be passed through a dilute aqueous

N i {S O}_{4}

solution during electrolysis using inert electrode, in order to get

5.85 g

N i = 58.5 g m

Q. A current of

9.65

ampere is passed through

0.2 M

500

ml aqueous solution of

C u S O_{4}

using Cu-electrode for

300 s e c

[C u^{+ 2}]

concentration in the resulting solution, if volume of solutions remains constant.

Q. (a) How many electrons flow through a metallic wire if a current of 0.5 ampere is passed for 2 hrs? (Given 1F = 96500 C/mol)
(b) Give the products obtained at cathode and anode during electrolysis of

A g N O_{3}

A g

N a O H

can also be prepared by electrolysis of aqueous

N a C l

N a O H

0.445 L

N a C l

(aq) is electrolysed for

137

s with a current of

1.08 A

0.06

g. The pH of this solution is :

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