A current i is flowing in a conductor as shown in the figure. The magnetic induction at point O will be :

zero

No worries! We‘ve got your back. Try BYJU‘S free classes today!

μ_{0} i / r

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2 μ_{0} i / r

No worries! We‘ve got your back. Try BYJU‘S free classes today!

μ_{0} i / 4 r

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $μ_{0} i / 4 r$
The magnetic induction at the center of the circular current carrying loop of radius r, is given by
$B = \frac{μ_{0} i}{2 r}$
For semicircular loop
$B^{'} = \frac{1}{2} B$
$B^{'} = (\frac{1}{2}) \frac{μ_{0} i}{2 r} = \frac{μ_{0} i}{4 r}$

Suggest Corrections

Similar questions

Q. In the figure shown there are two semicircles of radii

r_{1}

and

r_{2}

in which a current I is flowing. The magnetic induction at the centre O will be:

In the figure shown there are two semicircles of radii $r_{1}$ and $r_{2}$ in which a current i is flowing. The magnetic induction at the centre O will be

Q. A currrent of 30 amp is flowing in a conductor as shown in the figure. The magnetic induction at point O will be:

Q. A wire loop PQRSP is constructed by joining two semi-circular coils of radius

r_{1}

and

r_{2}

respectively, as shown in the figure. If the current flowing in the loop is I, then the magnetic induction at the point O is:

Q. Equal current

i

is flowing in two parallel infinite long conductors at distant

2 l

, in mutually opposite directions as shown in the figure. The magnetic induction at a point

p

equidistant

r

from both conductors will be :

Join BYJU'S Learning Program

A current i is flowing in a conductor as shown in the figure. The magnetic induction at point O will be :

The correct option is D μ0i/4rThe magnetic induction at the center of the circular current carrying loop of radius r, is given byB=μ0i2rFor semicircular loop B′=12BB′=(12)μ0i2r=μ0i4r

The correct option is D $μ_{0} i / 4 r$
The magnetic induction at the center of the circular current carrying loop of radius r, is given by
$B = \frac{μ_{0} i}{2 r}$
For semicircular loop
$B^{'} = \frac{1}{2} B$
$B^{'} = (\frac{1}{2}) \frac{μ_{0} i}{2 r} = \frac{μ_{0} i}{4 r}$