1
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Question

# A current of 1 A is drawn by a filament of an electric bulb. Number of electrons passing through a cross section of the filament in 16 seconds would be roughly:

A
1020
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B
1016
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C
1018
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D
1023
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Solution

## The correct option is A 1020Given : I=1A,t=16s,e=1.6×10−19CStep 1: Current drawn by the filamentI=Qt=Net (Since Q=Ne, where N is the number of electrons crossing in time t)⇒N=I te ....(1)Step 2: Substituting the values in equation (1) N=I te=1A×16s1.6×10−19C=1020Hence, number of electrons passing through a cross section of the filament in 16 seconds would be 1020.

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