CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

A current of (2.5±0.05) A flows through a wire and develops a potential difference of (10±0.1) volt.  Resistance of the wire in ohm, is 


  1. 4±0.012

  2. 4±0.4

  3. 4±0.08

  4. 4±0.02


Solution

The correct option is A

4±0.012


V=iRR=Vi,ΔR=[Δ VV+Δ ii]R=(4±0.012)Ω

flag
 Suggest corrections
thumbs-up
 
0 Upvotes


Similar questions
View More


People also searched for
View More



footer-image