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Question

A current of 3 A is flowing in a linear conductor having a length of 40 cm. The conductor is placed in a magnetic field of strength 500 gauss and makes an angle 30$$^o$$ with the direction of the field. It experiences a force of magnitude


A
3×104N
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B
3×102N
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C
3×102N
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D
3×104N
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Solution

The correct option is B $$3 \times 10^{-2} N$$
$$F = IL B  sin  \theta $$
$$= 3 \times 0.40  \times (500 \times 10^{-4}) \times sin 30^o$$
$$= 3 \times 10^{-2} N$$

Physics

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