Question

# A current of 3 A is flowing in a linear conductor having a length of 40 cm. The conductor is placed in a magnetic field of strength 500 gauss and makes an angle 30$$^o$$ with the direction of the field. It experiences a force of magnitude

A
3×104N
B
3×102N
C
3×102N
D
3×104N

Solution

## The correct option is B $$3 \times 10^{-2} N$$$$F = IL B sin \theta$$$$= 3 \times 0.40 \times (500 \times 10^{-4}) \times sin 30^o$$$$= 3 \times 10^{-2} N$$Physics

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