Question

A current of 9.65 Ampere flowing for 10 minutes deposits 3 g of metal which is monovalent, the atomic mass of metal is a:

• A. 10
• B. 50
• C. 30
• D. 96.5

Answer 1

The correct option is B 50

Solution:- (B) $50$

Weight of metal deposited $=3g$

Quantity of electricity passed $\left(q\right)$-

$q=I\times t$

Given:-

$I=9.65A$

$t=10min=10\times 60=600sec$

$\therefore q=9.65\times 600=5790C$

Now, as we know that,

Eq. wt. of metal $=\frac{\text{Weight of metal}}{q}\times F$

$\Rightarrow$ Eq. wt. of metal $=\frac{3}{5790}\times 96500=50g$

As the metal is monovalent, atomic weight of metal will be equal to its equivalent weight.

Therefore,

Atomic weight of metal $=50g$