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Standard XII

Chemistry

Faraday's First Law

A current of ...

Question

A current of 9.95 amperes flowing for 10 minutes, deposits 3g of metal. An equivalent weight of the metal is:

12.5

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18.5

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21.5

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48.5

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Solution

The correct option is A $48.5$
$∵ W = z . i . t \to 3 = \frac{E}{F} \times 9.95 \times 10 \times 60$
$∴ E = (\frac{3 \times 96500}{9.95 \times 10 \times 60})$ $= 48.5$

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A current of 9.95 amperes flowing for 10 minutes, deposits 3g of metal. An equivalent weight of the metal is:

The correct option is A 48.5∵W=z.i.t→3=EF×9.95×10×60 ∴E=(3×965009.95×10×60)=48.5

The correct option is A $48.5$
$∵ W = z . i . t \to 3 = \frac{E}{F} \times 9.95 \times 10 \times 60$
$∴ E = (\frac{3 \times 96500}{9.95 \times 10 \times 60})$ $= 48.5$