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A current of 9.65amperes flowing for 10minutesdeposits 3gof metal which is monovalent, the atomic mass of metal is:


A

10

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B

50

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C

30

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D

96.5

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Solution

The correct option is B

50


Step 1: Given data

Electric current passed, i=9.65A

Time period during which current flows, t=10min=10×60s=600s

Weight of metal deposited, w=3g

Atomic mass of the metal, ma=?

Valency, n=1

Step 2: Assumptions

Equivalent weight of the metal=we

Magnitude of Charge flowing =q

Faraday's constant, F=96500

Step 3: Formula used

q=i×t …………………………….(a)

we=wq×F ………………………(b)

ma=we×n………………………..(c)

Step 4: Calculation of the atomic mass of the metal

Substituting the given values in equation (a), we get

q=9.65A×600sq=5790C

Substituting the given values and the value of charge obtained above in the equation (b), we get

we=3g5790C×96500we=50g

Substituting the equivalent weight obtained above and the given valency of the metal in the equation (c), we get

ma=50g×1ma=50amu

Hence, option (B) is correct.


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