Question

# A current of $9.65amperes$ flowing for $10minutes$deposits $3g$of metal which is monovalent, the atomic mass of metal is:

A

$10$

No worries! We‘ve got your back. Try BYJU‘S free classes today!
B

$50$

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C

$30$

No worries! We‘ve got your back. Try BYJU‘S free classes today!
D

$96.5$

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

## The correct option is B $50$Step 1: Given dataElectric current passed, $i=9.65A$Time period during which current flows, $t=10min=10×60s=600s$Weight of metal deposited, $w=3g$Atomic mass of the metal, ${m}_{a}=?$Valency, $n=1$Step 2: AssumptionsEquivalent weight of the metal$={w}_{e}$ Magnitude of Charge flowing $=q$Faraday's constant, $F=96500$Step 3: Formula used$q=i×t$ …………………………….(a)${w}_{e}=\frac{w}{q}×F$ ………………………(b)${m}_{a}={w}_{e}×n$………………………..(c)Step 4: Calculation of the atomic mass of the metalSubstituting the given values in equation (a), we get$q=9.65A×600s\phantom{\rule{0ex}{0ex}}q=5790C$Substituting the given values and the value of charge obtained above in the equation (b), we get${w}_{e}=\frac{3g}{5790C}×96500\phantom{\rule{0ex}{0ex}}{w}_{e}=50g$Substituting the equivalent weight obtained above and the given valency of the metal in the equation (c), we get${m}_{a}=50g×1\phantom{\rule{0ex}{0ex}}{m}_{a}=50amu$Hence, option (B) is correct.

Suggest Corrections
0