    Question

# A current transformer has a single turn primary and 400 turns on secondary winding. The resistance annd reactance of the secondary circuit are 2Ω and 3Ω respectively including transformer winding. When 6 A current is flowing in the secondary winding, the magnetizing mmf is 100AT and iron loss is 2W. The value of ratio error will be

A
3.42%
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
4.14%
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
2.24%
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
1.62%
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

## The correct option is B −4.14%Primary winding turns, NP=1 Secondary winding turns, Ns=400 Turn ratio, n=NSNP=400 Seconday circuit burden impedance =√(2)2+(3)2=3.606Ω For secondary winding circuit. cosδ=23.606=0.554 and, sinδ=33.606=0.832 Secondary induced voltage ES=6×3.606 =21.64V Primary inuced voltage EP=ESn=21.64400=0.054V Loss component of current referred to primary winding Ic=Iron lossE=20.054=37.04A Magnetizing current, Im=Magnetizing mmfPrimary winding turns=1001=100A Acutal ratio, R=n+IC cosδ+Im sin δIS =400+37.04cosδ+100sinδIs =400+103.726=400+17.28 =417.28 Percentage ratio error =Kn−RR×100; Where Ka= nominal ratio =400−417.28417.28×100=−4.14%  Suggest Corrections  0      Similar questions
Join BYJU'S Learning Program
Select...  Related Videos   MEASUREMENT
Watch in App  Explore more
Join BYJU'S Learning Program
Select...