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Question

A cyclist starts from centre O of a circular park of radius 1 km and moves along the path OPRQO as shown in figure. If he maintains constant speed of 10 $$ms^{-1}$$, what is his acceleration at point R ? 
940463_8c3589e58a104f1a950707a20a0f6b1d.JPG


A
10 ms2
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B
0.1ms2
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C
0.01ms2
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D
1ms2
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Solution

The correct option is D 0.1$$ms^{-2}$$
The acceleration at point $$R$$ is towards the center of the circle.
Here, $$v = 10 ms^{-1}$$, $$r = 1 km = 1000 m$$
Centripetal acceleration, 
$$a_{c}=\dfrac{v^{2}}{r}$$

    $$=\dfrac{(10 ms^{-1})^{2}}{1000 m} = 0.1 ms^{-2}$$

Physics

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