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Standard XII

Physics

Uniform Circular Motion

A cyclist sta...

Question

A cyclist starts from centre O of a circular park of radius 1 km and moves along the path OPRQO as shown in figure. If he maintains constant speed of 10 $m s^{- 1}$ , what is his acceleration at point R ?

m s^{- 2}

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0.1

m s^{- 2}

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0.01

m s^{- 2}

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m s^{- 2}

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Solution

The correct option is D 0.1 $m s^{- 2}$
The acceleration at point $R$ is towards the center of the circle.
Here, $v = 10 m s^{- 1}$ , $r = 1 k m = 1000 m$
Centripetal acceleration,
$a_{c} = \frac{v^{2}}{r}$

$= \frac{(10 m s^{- 1})^{2}}{1000 m} = 0.1 m s^{- 2}$

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A cyclist starts from centre O of a circular park of radius 1 km and moves along the path OPRQO as shown in figure. If he maintains constant speed of 10 ms−1, what is his acceleration at point R ?

The correct option is D 0.1ms−2The acceleration at point R is towards the center of the circle.Here, v=10ms−1, r=1km=1000mCentripetal acceleration, ac=v2r =(10ms−1)21000m=0.1ms−2

A cyclist starts from centre O of a circular park of radius 1 km and moves along the path OPRQO as shown in figure. If he maintains constant speed of 10 $m s^{- 1}$ , what is his acceleration at point R ?

The correct option is D 0.1 $m s^{- 2}$
The acceleration at point $R$ is towards the center of the circle.
Here, $v = 10 m s^{- 1}$ , $r = 1 k m = 1000 m$
Centripetal acceleration,
$a_{c} = \frac{v^{2}}{r}$

$= \frac{(10 m s^{- 1})^{2}}{1000 m} = 0.1 m s^{- 2}$