Question

A cylinder containing cooking gas can withstand a pressure of 15 atm. The pressure gauge of the cylinder indicates 12 atm at ${27}^{\circ }C$. Due to a sudden fire in the building, the temperature starts rising. At what temperature will the cylinder explode?

• A.
• B.
• C.
• D.

Answer 1

The correct option is C

Given, $P_1$ = 15 atm, $T_1$ = ?

$P_2$ = 12 atm, $T_2$ = 300 K (273+27)

Since the volume of the cylinder remains constant,
$\frac{P_1}{T_1}=\frac{P_2}{T_2}$

Therefore,$\frac{15}{T_1}=\frac{12}{300}$

$T_1$ = 375 K.

i.e., the cylinder will explode above 375 K or ${102}^{\circ }C$.