Question

# A cylinder of radius $$R$$ and length $$L$$ is placed in a uniform electric field $$E$$ parallel to the cylinder axis. The total flux for the surface of the cylinder is given by :

A
2πR2E
B
πR2E
C
RE
D
Zero

Solution

## The correct option is D ZeroFlux through surface $$A$$,$${ \phi }_{ A }=E\times \pi { R }^{ 2 }$$$${ \phi }_{ B }=-E\times \pi { R }^{ 2 }$$Flux through curved surface, $$C=\displaystyle\int { E.ds }$$                                                   $$=\displaystyle\int { Eds } \cos { { 90 }^{ o } } =0$$$$\therefore$$ Total flux through cylinder $$={ \phi }_{ A }+{ \phi }_{ B }+{ \phi }_{ C }=0$$Physics

Suggest Corrections

0

Similar questions
View More

People also searched for
View More