Question

A cylindrical tank $16$ m long and $23$ m wide contains water. How many cubic metres of water must be rushed into it to make the surface rise by $16\frac{2}{3}$ cm ?

• A. $48m^3$
• B. $40.57m^3$
• C. $69.35m^3$
• D. $42m^3$

Answer 1

The correct option is C $69.35m^3$

The volume of a tank of height $16$ m and diameter $23$ m is given as, $\pi r^{2}h$

$\therefore$ Volume of tank $=3.14\times 11.5\times 11.5\times 16=6644.24m^3$

If the surface raises by $16\frac{2}{3}$ cm, then the new $h=16$ m $+\frac{50}{3}$cm $=16+0.167=16.167$ m

$\therefore$ New volume is $=3.14\times 11.5\times 11.5\times 16.167=6713.59m^3$

Hence, $6713,59-6644.24=69.35$ cubic metres of water must be rushed into it to make the surface rise by $16\frac{2}{3}$ cm.