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Question

A cylindrical tank of radius r and wall thickness t has flat end closures. The tank is subjected to an internal pressure P. The longitudinal (σl) and the circumferential (σh) stresses respectively are given by:

A
Pr/t, 0
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B
Pr/2t, Pr/t
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C
Pr/4t, Pr/3t
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D
Pr/6t, Pr/t
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Solution

The correct option is B Pr/2t, Pr/t
Hoop or circumferential stress




p×l×d=σh×2l×t

σh=Pd2t

d = inner diameter
t = thickness
p = fluid pressure

No shear exists on the section on which Hoop stress acts.

. Hence,σh= pd2t is a principal stress.

σh is always tensile both in thick shells as well as in thin shells due to fluid pressure from inside. However for outside pressure σh will be compressive.

Longitudnal Stress (σl)



πd24×p=σl×π(d+2×t2)×t

=σl×π(d+t)t

Neglecting, t2 term, as it is very small as compared to (d x t)

πd24×p=σl×πdt

σl=pd4t

As no shear, acts on section on which
σl is actingσl=principal stress.

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