A dealer sold a camera for $R s . 1080$ gaining $\frac{1}{8}$ of its cost price. Find:
i) the cost price of the camera
ii) the gain per cent earned by the dealer.

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Solution

Cost of camera dealer sold= $R s . 1080$
cost price of camera $= R s . x$
A/c the question
$x + \frac{1}{8} x = 1080$
$\Rightarrow x = (\frac{9}{8}) = 1080$
$x = \frac{(1080) 8}{9} = (120) 8 = 960$
cost price of
camera $= R s . 960$
$%$ gain = $\frac{1080 - 960}{960} \times 100 = 12.5 %$

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A dealer sold a camera for Rs.1080 gaining 18 of its cost price. Find:i) the cost price of the cameraii) the gain per cent earned by the dealer.

Cost of camera dealer sold= Rs.1080cost price of camera =Rs.xA/c the questionx+18x=1080⇒x=(98)=1080x=(1080)89=(120)8=960cost price of camera =Rs.960% gain =1080−960960×100=12.5%

A dealer sold a camera for $R s . 1080$ gaining $\frac{1}{8}$ of its cost price. Find:
i) the cost price of the camera
ii) the gain per cent earned by the dealer.

Cost of camera dealer sold= $R s . 1080$
cost price of camera $= R s . x$
A/c the question
$x + \frac{1}{8} x = 1080$
$\Rightarrow x = (\frac{9}{8}) = 1080$
$x = \frac{(1080) 8}{9} = (120) 8 = 960$
cost price of
camera $= R s . 960$
$%$ gain = $\frac{1080 - 960}{960} \times 100 = 12.5 %$