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A decimolar solution K4[Fe(CN)6] (potassium ferrocyanide) is 50% dissociated at 300K. Calculate the osmotic pressure of the solution.

A
6.2 atm
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B
7.4 atm
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C
5.4 atm
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D
7.9 atm
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Solution

The correct option is A 7.4 atm
K4[Fe(CN)6]4K++[Fe(CN)6]4
One molecule of K4[Fe(CN)6] dissociates to give 5 ions.
Since K4[Fe(CN)6] is 50% dissociated, if we start with 2 molecules of K4[Fe(CN)6], one molecule of K4[Fe(CN)6] will dissociate to provide 5 ions and one molecule of K4[Fe(CN)6] remains undissociated. Thus, from two molecules of K4[Fe(CN)6], we get 6 particles.
The Van't Hoff's factor i=actual number of particlesexpected number of particles=62=3
The osmotic pressure π=iCRT
π=3×0.1 mol/L×0.08206 Latm/mol/K×300 K
π=7.4 atm
Note: Decimolar means 0.1 mol/L

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