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Question

A decimolar solution of potassium ferrocyanide at 300 K is 50% dissociated. Calculate the osmotic pressure of the solution.
R=0.082 L atm mol1 K1.

A
π=14.18 atm
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B
π=7.38 atm
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C
π=1.45 atm
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D
π=21.91 atm
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Solution

The correct option is B π=7.38 atm
K4Fe(CN)64K++[Fe(CN)6]4

As one molecule of potassium ferrocyanide dissociates into five particles.
So, n=5
Degree of dissociation, α=50%=0.5
For dissociation,
α=i1n1

0.5=i151

i=3

Osmotic pressure, (π)=iCRT

Given:

Concentration, C=110 mol L1

R=0.082 L atm mol1 K1

T=300 K

π=3×1×0.082×30010π=7.38 atm

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