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Question

A decimolar solution of potassium ferrocynide is 50% dissociated at 300 K. Given S=8.314JK1 mol1. The osmotic pressure of the solution is :

A
7.438×105 Nm2
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B
7.834×105 Nm2
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C
7.348×105 Nm2
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D
7.483×105 Nm2
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Solution

The correct option is D 7.483×105 Nm2
We have molarity=nV=0.1 mol litre1=0.1103mol m3=102 mol m3As, πN×V=nSTOr, πN=(nV)ST=102×8.314×300 Nm2Let degree of association be α,Therefore, for K4Fe(CN)64K++Fe(CN)46
1 0 0
1α 4α α
It is given that α=0.5
And πexpπN=1+4αTherefore, πexp=πN(1+4α)==102×8.314×300×(1+4×0.5)=102×8.314×300×(1+2)=7.483×105 Nm2

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