A denser medium of refractive index 1.5 has a concave surface of radius of curvature 12 cm. An object is situated in the denser medium at a distance of 9 cm from the pole .locate the image due to refraction in air.
Step 1: Given that:
The refractive index of denser medium= 1.5
Radius of curvature(R) = 12cm
Object distance(u)= 9cm
Step 2: Calculation of image distance:
According to the refraction formula from denser to medium to rare medium,
μ1 = Refractive index of rare medium
μ2 = Refractive index of denser medium
Thus, putting all the values, we get
Thus, the image distance will be 8cm .