Question

# A dice is thrown two times and the sum of the scores appearing on the dice is observed to be a multiple of 4. Then the conditional probability that the score 4 has appeared atleast once is

A
13
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B
14
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C
18
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D
19
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Solution

## The correct option is D 19A: Sum obtained is a multiple of 4. A={(1,3),(3,1), (2,6),(6,2), (3,5),(5,3), (2,2),(4,4),(6,6)} B: Score of 4 has appeared at least once. ​​B={(1,4),(2,4),(3,4),(4,4),(5,4),(6,4), (4,1),(4,2),(4,3),(4,5),(4,6)} From A and B, (A∩B)=(4,4), n(A∩B)=1 Required probability =P(BA)=P (A∩B)P (A)=136936=19

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