A die is rolled $300$ times and following outcomes are recorded :
Outcome $1$ $2$ $3$ $4$ $5$ $6$
Frequency $42$ $60$ $55$ $23$ $60$ $30$
Find the probability of getting a number
(i) more than $4$
(ii) less than $3.$

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Solution

No .of times die rolled is $300$

(i) More than $4$

The frequencies are $60 + 30 = 90$

Probability is given as $\frac{90}{300} = \frac{3}{10}$

(i) Less than $3$

The frequencies are $42 + 60 = 102$

Probability is given as $\frac{102}{300} = \frac{17}{50}$

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