A die is thrown and a card is selected at random from a deck of 52 playing cards. The probability getting an even number on the die and a spade card is
A
1/2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
1/4
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
1/8
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
3/4
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is C 1/8 Let E1 = Event for getting an even number on the die And E2=Event that a spade card is selected ∴P(E1)=36=12 and P(E2)=1352=14 Then, P(E1∩E2)=P(E1)⋅P(E2)=12⋅14=18