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Question

A die is thrown and a card is selected at random from a deck of 52 playing cards. The probability getting an even number on the die and a spade card is


A
1/2
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B
1/4
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C
1/8
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D
3/4
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Solution

The correct option is C 1/8
Let $$E_1$$ = Event for getting an even number on the die 
And $$E_2$$=Event that a spade card is selected 
$$\therefore P(E_1)=\dfrac{3}{6}=\dfrac{1}{2}$$ and $$P(E_2)=\dfrac{13}{52}=\dfrac{1}{4}$$
Then, $$P(E_1\cap E_2)=P(E_1)\cdot P(E_2)=\dfrac{1}{2}\cdot\dfrac{1}{4}=\dfrac{1}{8}$$

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