A die is thrown, find the probability of getting an even number.

\frac{1}{2}

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\frac{1}{3}

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\frac{2}{3}

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None of these

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Solution

The correct option is A $\frac{1}{2}$
A die is thrown.
Total outcomes: $6 \to {1, 2, 3, 4, 5, 6}$
Total even number: $3 \to {2, 4, 6}$
Required probability:
$P = \frac{3}{6} = \frac{1}{2}$

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Similar questions

2) A die is thrown. Find the probability of getting a) a number 2 b) an even number c) a number greater than 2

A die is thrown once. The probability of getting an even number is
(a) $\frac{1}{2}$ (b) $\frac{1}{3}$ (c) $\frac{1}{6}$ (d) $\frac{5}{6}$

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