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Question

A die is thrown once. Find the probability of getting a number:
i)less than 3
ii)greater than or equal to 4
iii)less than 8
iv)greater than 6.

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Solution

A die is thrown once,

The possible outcomes ={1,2,3,4,5,6}

i.e., n(S)=6

(i) Probability of getting a number less than 3=n(E)n(S)=26=13

(ii) Probability of getting a number greater than or equal to 4=n(E)n(S)=46=23

(iii) Probability of getting a number less than 8=n(E)n(S)=66=1

(iv) Probability of getting a number greater than 6=n(E)n(S)=06=0



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