A die is thrown once. The probability of getting an even number is
(a) $\frac{1}{2}$ (b) $\frac{1}{3}$ (c) $\frac{1}{6}$ (d) $\frac{5}{6}$

Open in App

Solution

The outcomes when a die is thrown are - 1,2,3,4,5,6

so the total outcome = 6
even numbers are 2 , 4 , 6
so it is 3
therefore the probability of getting a even number is 3/6 = 1/2

answer :- (a) 1/2

Suggest Corrections

Similar questions

A die is thrown once. The probability of getting an odd number greater than 3 is
(a) $\frac{1}{3}$ (b) $\frac{1}{6}$ (c) $\frac{1}{2}$ (d) 0

A die is thrown once. The probability of getting a prime number is
(a) $\frac{2}{3}$ (b) $\frac{1}{3}$ (c) $\frac{1}{2}$ (d) $\frac{1}{6}$

Join BYJU'S Learning Program