Question

A die is thrown once. The probability of getting an even number is [CBSE 2013]

(a) $\frac{1}{2}$
(b) $\frac{1}{3}$
(c) $\frac{1}{6}$
(d) $\frac{5}{6}$

Answer 1

​Total number of outcomes = 6.

Out of the given numbers, even numbers are 2, 4 and 6.

Numbers of favourable outcomes = 3.

∴ P(getting an even number) = $\frac{\mathrm{Number}\mathrm{of}\mathrm{favourable}\mathrm{outcomes}}{\mathrm{Number}\mathrm{of}\mathrm{all}\mathrm{possible}\mathrm{outcomes}}$
= $\frac{3}{6}=\frac{1}{2}$

Thus, the probability of getting an even number is $\frac{1}{2}$.

Hence, the correct answer is option (a).