Question

A die is thrown once. The probability of getting an odd number greater than 3 is
(a) $\frac{1}{3}$ (b) $\frac{1}{6}$ (c) $\frac{1}{2}$ (d) 0

Answer 1

Possibles outcomes in a single throw of a die is

{1,2,3,4,5,6} = 6

let E = Getting a number greater than 3 and odd.

There are three numbers {4,5,6} which is greater than 3

so, required probability P(E) = 1/6

Answer:- (b) 1/6