A die is tossed 250 times and the data is recorded as below:

Outcome 1 2 3 4 5 6

Frequency 30 50 50 75 20 25

The probability of getting an odd number is

\frac{1}{2}

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\frac{2}{3}

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\frac{2}{5}

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\frac{3}{5}

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Solution

The correct option is C $\frac{2}{5}$
Total number of times, a die is thrown = 250
Outcomes having an odd number are 1, 3 or 5.
$∴ Number of favourable outcomes = 30 + 50 + 20 = 100$
$∴ P(getting an odd number) = \frac{Number of favourable outcomes}{Total number of outcomes}$
$= \frac{100}{250}$
$= \frac{2}{5}$

Hence, the correct answer is option (c).

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Similar questions

200

$O u t c o m e \Rightarrow$	$1$	$2$	$3$	$4$	$5$	$6$
$F r e q u e n c y \Rightarrow$	$25$	$35$	$40$	$28$	$42$	$30$

3

\begin{matrix} O u t c o m e & 1 & 2 & 3 & 4 & 5 & 6 F r e q u e n c y & 25 & 30 & 15 & 28 & 32 & 20 \end{matrix}

Outcomes	1	Odd number greater than 1	Even number
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Outcome	$1$	$2$	$3$	$4$	$5$	$6$
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1, 2, 3, 4, 5, 6

Outcome	$1$	$2$	$3$	$4$	$5$	$6$
Frequency	$40$	$38$	$43$	$29$	$28$	$22$

Find the probabilities of getting a number more than $1$ and less than $6$ in a toss (trial).

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