A dihybrid plant on self pollination produced 400 phenotypes with 9 types of genotype. How many seeds will have genotype TtRr?

200

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100

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150

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Solution

The correct option is B 100
The self pollination of a dihybrid plant yields the genotypic ratio of 1 TTRR : 2 TTRr : 1 TTrr : 2 TtRR : 4TtRr : 2 Ttrr : 1ttRR : 2 ttRr : 1 ttrr. The ratio of genotype TtRr is 4/16. Hence, out of total 400 phenotypes, number of seeds having TtRr genotype will be 4/16x400 = 100. Option "B" is correct.
F $_{1}$ generation : TtRr x TtRr
Gametes :
TtRr -->
TtRr TR Tr tR tr
TR TTRR TTRr TtRR
TtRr
Tr TTRr TTrr TtRr Ttrr
tR TtRR TtRr ttRR ttRr
tr TtRr Ttrr ttRr ttrr

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Gametes : TtRr --> TtRr	TR	Tr	tR	tr
TR	TTRR	TTRr	TtRR	TtRr
Tr	TTRr	TTrr	TtRr	Ttrr
tR	TtRR	TtRr	ttRR	ttRr
tr	TtRr	Ttrr	ttRr	ttrr