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Question

A dip needle lies initially in the magnetic meridian when it shows an angle of dip θ at a place. The dip circle is rotated through an angle x in the horizontal plane and then it shows an angle of dip θ. Then tan θtan θ is

A
1cos x
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B
1sin x
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C
1tan x
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D
cosx
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Solution

The correct option is A 1cos x
Here,
θActual dip

θ Apparent dip

x Angle of plane with respect to the magnetic meridian.

Then, tanθ=BVBH ......(1)

tanθ=BVBHcosx ......(2)

Dividing equation (1) and (2) we have,

tan θtan θ=1cos x

Hence, option (A) is the correct answer.

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